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Power factor correction calculator

Motors, transformers and ballasts need reactive power to build their magnetic field. That energy flows back and forth through the installation without doing work, but it raises the current, heats the cables and, on many supplies, it is charged for. A capacitor bank supplies it next to the load and raises the power factor (cos φ). This calculator gives the kVAR of the bank and the µF of each capacitor.

How it is calculated

Q = P × (tan φ₁ − tan φ₂)

P is the active power, φ₁ the angle for the current power factor and φ₂ the one for the target. From the kVAR you get the capacitance of each capacitor (V is the line-to-line voltage and f the frequency):

Example

A plant drawing 50 kW at a power factor of 0.75 that wants to reach 0.95: tan φ₁ = 0.882 and tan φ₂ = 0.329, so Q = 50 × (0.882 − 0.329) ≈ 27.7 kVAR. With delta-connected capacitors at 400 V and 50 Hz, each one about 183 µF. The current drops from 96 A to 76 A, 21 % less. At 480 V and 60 Hz the same bank would need about 106 µF per capacitor.

Why correct the power factor

How it is done in practice

SafetyCapacitors keep their charge after disconnection. Banks have discharge resistors: wait the time stated by the manufacturer and verify that there is no voltage before touching.
Typical mistakeSizing the capacitors as if they were in star and connecting them in delta, or the other way round. In delta each capacitor gets the line-to-line voltage and needs three times less capacitance.

To understand the topic in depth: Practical electrical theory, with theory and a practice test.

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